Why Doesn't This Work

Mar 2015
1,720
126
New Jersey
Consider Ax=0

\(\displaystyle \begin{vmatrix}
a_1_1\\
a_2_1\\
a_3_1\\
a_4_1\\
a_5_1
\end{vmatrix}x_1 + \begin{vmatrix}
a_1_2\\
a_2_2\\
a_3_2\\
a_4_2\\
a_5_2
\end{vmatrix} x_2 +\begin{vmatrix}
a_1_3\\
a_2_3\\
a_3_3\\
a_4_3\\
a_5_3
\end{vmatrix} x_3 =0\)
 
Last edited:
Mar 2015
1,720
126
New Jersey
But this works!?

\(\displaystyle \begin{pmatrix}
a1 &a2 &a3 \\
b1 &b2 &b3
\end{pmatrix} x_1=0\)
 
Mar 2015
1,720
126
New Jersey
\(\displaystyle \begin{vmatrix}
a11\\
a21\\
a31\\
a41\\
a51
\end{vmatrix}x1+\begin{vmatrix}
a12\\
a22\\
a32\\
a42\\
a52
\end{vmatrix}x2+\begin{vmatrix}
a13\\
a23\\
a33\\
a43\\
a53
\end{vmatrix}x3=0\)

It didn't like double subscripts in the matrix. a1_1 ok, a_1_1 ng
 

skipjack

Forum Staff
Dec 2006
21,309
2,379
I suspect you want this:

\(\displaystyle \begin{vmatrix}
a_{11} \\
a_{21} \\
a_{31} \\
a_{41} \\
a_{51}
\end{vmatrix}x_1 + \begin{vmatrix}
a_{12} \\
a_{22} \\
a_{32} \\
a_{42} \\
a_{52}
\end{vmatrix} x_2 +\begin{vmatrix}
a_{13} \\
a_{23} \\
a_{33} \\
a_{43} \\
a_{53}
\end{vmatrix} x_3 = 0\)
 
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