D dome34 Jan 2020 3 0 Croatia Jan 8, 2020 #1 Hi, I have a problem which needs to be solved without using L'Hosiptal rule. Can anyone help me?

skeeter Math Team Jul 2011 3,206 1,731 Texas Jan 8, 2020 #2 try the substitution $u=\sqrt[6]{\cos{x}}$ ... limit = $-\dfrac{1}{12}$ Reactions: idontknow

I idontknow Dec 2015 935 122 Earth Jan 9, 2020 #3 now the limit is \(\displaystyle \lim_{u\rightarrow 1 } \dfrac{u^3 - u^2 }{1-u^{12} }\).

I idontknow Dec 2015 935 122 Earth Jan 9, 2020 #5 dome34 said: Is the following substitution correct? cosx = t^6 Click to expand... Yes.