Possible to find at least 1 indefinite value in 5 related procedures?

zrs

Jan 2017
1
0
Turkey
I have 5 procedures listed below:

1. (x+y+z)/x1=252.81

2. (x+1.5y+z)/x1=292.13

3. (2x+1.5y+z)/x1=449.44

4. (2x+2y+2z)/x1=505.62

5. (3x+2y+2z)/x1=662.92

x, y, z & x1 are variables but used same in each procedures. Considering the related procedures what is the possibility to find at least one of the value assigned to x or y? If not possible from the given data the proximate value of z can be estimated but x, y, & x1 are always unpredictable.

The required values in procedures above are:

1. (140+70+15)/0.89=252.81

2. (140+105+15)/0.89=292.13

3. (280+105+15)/0.89=449.44

4. (280+140+30)/0.89=505.62

5. (420+140+30)/0.89=662.92

Thanks in advance.
 
Last edited:

mathman

Forum Staff
May 2007
6,895
760
Equation 4 is equation 1 times 2, therefore not independent. You have 4 equations in four unknowns.