\(\displaystyle \frac{1}{4}\left[(2x^2-1)\arcsin x - \!\int \frac {2x^2-1}{\sqrt{1-x^2}}dx\right]\). I don't have any idea how the second part is solved.

I mean this part: \(\displaystyle (- \!\int \frac {2x^2-1}{\sqrt{1-x^2}}dx)\).

Thank you all.

- Thread starter shadow dancer
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