# Logarithms

#### Gold Boy

Hi again,
‘I got two logarithm I need help with. My first one I got stuck (has red star where I got stuck) and I need further steps, while my second one “(B)” my answer was wrong and I need help why.

#### Gold Boy

My second problem. The third term on the far right natural log “z” and not “2.”

#### Attachments

• 441.5 KB Views: 2

#### skipjack

Forum Staff
$$\displaystyle \ln\left(\frac{x^{-1/7}\cdot2^{1/7}}{y^{1/7}}\right) = \ln\left(\frac{2^{1/7}}{x^{1/7}y^{1/7}}\right)$$

$$\displaystyle \log_4\left(\frac{\sqrt{x}}{y^3z}\right)$$

topsquark
Similar Math Discussions Math Forum Date
Calculus
Algebra
Algebra
Calculus