\(\displaystyle \int \frac{x \cdot \cosh (x)}{(\sinh (x))^2}dx = ?\)

By doing substitution(?) \(\displaystyle u= \csch (x)\) I got \(\displaystyle -u \cdot \text{arccsch}(u) - \text{arcsinh}(u)\).

Can someone re-simplify \(\displaystyle \text{arcsinh}(u)\) for me?

By doing substitution(?) \(\displaystyle u= \csch (x)\) I got \(\displaystyle -u \cdot \text{arccsch}(u) - \text{arcsinh}(u)\).

Can someone re-simplify \(\displaystyle \text{arcsinh}(u)\) for me?

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