I am not sure I should post this on calculus forum, but I need help.

I want to prove that if x is a composite number and x <= n, where n is a

natural number,

there are i and j naturals, so that 1 < i <= [n/2]

([]-means floor value)

and 2 <= j <= [n/i], that making i*j = x.

I want to prove that if x is a composite number and x <= n, where n is a

natural number,

there are i and j naturals, so that 1 < i <= [n/2]

([]-means floor value)

and 2 <= j <= [n/i], that making i*j = x.

Last edited by a moderator: