The diagram from below shows a block being pulled by a wire. The block's mass is $10\,kg$ and it moves horizontally from point $A$ to point $B$ due a constant force labeled $\vec{F}$ whose modulus is $40\,N$. Find the work done by the force $F$. The distance between $AB$ is $3.5 m$.

The alternatives in my book are:

$\begin{array}{ll}

1.&400\,J\\

2.&300\,J\\

3.&140\,J\\

4.&100\,J\\

\end{array}$

Initially I thought that the work can be found using this formula:

$W=F \cdot d$

Since they mention $F= 40\,N$:

$W=F\cos 37^{\circ}\cdot 3.5=\left(40\right)\left(\frac{4}{5}\right)\left(3.5\right)$

$W=112\,J$

However this doesn't seem right as I believe the work done by pulling the wire is measured by the distance which is traveled by the wire and not by the block.

It is kind of a strange setting as I cannot imagine a block which stays in the ground as is being pulled as it is described.

My instinct tells me that it has something to do with the horizontal distance in the sense that the distance which will be doing the force is the difference between the hypotenuse of the triangle from A to the pulley minus B to the pulley. But these distances aren't exactly given.

This is the part where I'm stuck. Can somebody help me with this please?. :help: