A body whose mass is $1\,kg$ is sliding over an incline of $5\,m$ in length. One of its sides has an elevation of $3\,m$ with respect of the floor. The other is resting in the floor. Find the horizontal distance which the body will travel before it stops. The coefficient of friction is constant all the path and is $0.125$.

The alternatives given in my book are:

$\begin{array}{ll}

1.&20\,m\\

2.&2.5\,m\\

3.&40\,m\\

4.&28\,m\\

5.&24.5\,m\\

\end{array}$

This problem doesn't offer a drawing or any sketch. So I made one by my interpretation of the words stated.

As it can be seen it was pretty simple to spot that they were referring to a $3-4-5$ right triangle. However the part where it gets tricky is. How to find the acceleration or something like this in order to find the horizontal distance?.

My initial idea was to use this formula:

$v_{f}^2=v_{o}^2-2a\Delta x$

Since it mentions that it will stop I can assume that the final speed is $0$. But in this case There isn't given a initial speed or anything that I could use.

What would be the answer?. What should be done to solve this problem?. Can somebody help me here?. :help: