In a race track an orange car $A$ is moving to the north ($\textrm{Y-axis}$) at a rate of $20\frac{m}{s}$ with respect to that a tv cameraman who is at a point labeled $O_{1}$ in the ground. Simultaneously another car (blue) $B$ is moving to the direction known as $N53^{\circ}O$ at $25\frac{m}{s}$ with respect to that another cameraman $O_{2}$. If the second cameraman $O_{2}$ is holding a camera in a dolly moving to the same direction of the blue car $B$ and the velocity $v_{o_{2}o}$ is $5.0\,\frac{m}{s}$. Find the velocity of the blue car $B$ with respect to that $A$ in $\frac{m}{s}$.

The given alternatives on my book are:

$\begin{array}{ll}

1.&-15\hat{i}+4\hat{j}\frac{m}{s}\\

2.&-24\hat{i}-2\hat{j}\frac{m}{s}\\

3.&-15\hat{i}-2\hat{j}\frac{m}{s}\\

4.&+26\hat{i}+2\hat{j}\frac{m}{s}\\

5.&-26\hat{i}+4\hat{j}\frac{m}{s}\\

\end{array}$

Okay I'm lost with this problem. Essentially my source of confusion is

**how**should I understand

$v_{o_{2}o}= 5.0\,\frac{m}{s}$

My only guess here is that what the author intended to explain was that the velocity of the blue car with respect to that the first cameraman is $5\frac{m}{s}$. But other than that. I don't know exactly what else should I do with the given information to work with the given bearing angles.

Can somebody help me here?.