B burgess Jun 2014 49 2 Brighton Jul 4, 2014 #1 Help required to solve algebra 2 homework A can do a piece of work in 5 days, but with the help of B,A can do it in 3 days. In how much time B alone can complete the same piece of work ? Thanks

Help required to solve algebra 2 homework A can do a piece of work in 5 days, but with the help of B,A can do it in 3 days. In how much time B alone can complete the same piece of work ? Thanks

S soroban Math Team Dec 2006 3,267 408 Lexington, MA Jul 4, 2014 #2 Hello, burgess! $A$ can do a piece of work in 5 days, but with the help of $B$, $A$ can do it in 3 days. In how much time can $B$ alone complete the same piece of work? Click to expand... $A$ does the job in 5 days. $\quad$In one day, $A$ does $\tfrac{1}{5}$ of the job. $B$ does the job in $b$ days. $\quad$In one day, $B$ does $\tfrac{1}{b}$ of the job. In one day, working together, they can do $\tfrac{1}{5} + \tfrac{1}{b}$ of the job. We are told that, working together, they can do the job in 3 days. That is, in one day, working together, they can do $\tfrac{1}{3}$ of the job. There is our equation! . . . $\dfrac{1}{5} + \dfrac{1}{b} \;=\;\dfrac{1}{3}$ Solve for $b$.

Hello, burgess! $A$ can do a piece of work in 5 days, but with the help of $B$, $A$ can do it in 3 days. In how much time can $B$ alone complete the same piece of work? Click to expand... $A$ does the job in 5 days. $\quad$In one day, $A$ does $\tfrac{1}{5}$ of the job. $B$ does the job in $b$ days. $\quad$In one day, $B$ does $\tfrac{1}{b}$ of the job. In one day, working together, they can do $\tfrac{1}{5} + \tfrac{1}{b}$ of the job. We are told that, working together, they can do the job in 3 days. That is, in one day, working together, they can do $\tfrac{1}{3}$ of the job. There is our equation! . . . $\dfrac{1}{5} + \dfrac{1}{b} \;=\;\dfrac{1}{3}$ Solve for $b$.