User Name Remember Me? Password

 Trigonometry Trigonometry Math Forum

 April 23rd, 2009, 10:30 AM #1 Newbie   Joined: Apr 2009 Posts: 3 Thanks: 0 Trig Interval Question I solved each problem, so if someone can check them I would appreciate it! 1. Solve the equation in the interval [0,2pi) tanxcosx-cosx=0 I found all solutions of the equation to be Cos: pi/2 +2npi ; 3pi/2 + 2npi The problem is both yield error when plugging into a calc so do I just exclude? n is any integer Tan: pi/4 +npi (this is just pi instead of 2pi because one period of tan is from (-pi/2, pi/2) If the question asks for the solutions in the interal [0,2pi) then the answers would just be pi/4? 2. Solve the equation in the interval [0,2pi) 2 cos^2x+sinx=1 For all solutions of the above I got 7pi/6 + 2npi; 11pi/6 + 2npi; pi/2 + 2npi So, for the interval [0,2pi] would it just be pi/2, 7pi/6, 11pi/6 April 23rd, 2009, 10:42 AM #2 Newbie   Joined: Apr 2009 Posts: 3 Thanks: 0 Re: Trig Interval Question Here is some additional work for #1 and #2 1. tanxcosx-cosx=0 cosx(tanx-1)=0 cosx=0 thus x is pi/2 and 3pi/2 but when checked yields error tanx=1 @pi/4 2. 2cos^2x+sinx=1 2(1-sin^2x)+sinx-1=0 2-2sin^2x+sinx-1=0 -2sin^2x+sinx+1=0 -1(2sinx+1)(sinx-1)=0 2sinx+1=0 sin x=-1/2 @7pi/6 and 11pi/6 sinx-1=0 sin x =1 @pi/2 Tags interval, question, trig Search tags for this page
,

# 1/sinx cosx interal

Click on a term to search for related topics.
 Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post lilyungn Advanced Statistics 0 June 20th, 2010 04:13 PM TsAmE Calculus 7 April 29th, 2010 11:23 AM 450081592 Calculus 2 November 15th, 2009 07:23 PM Kat-M Advanced Statistics 0 May 12th, 2009 10:26 AM sampimpinthug Algebra 2 June 14th, 2008 05:05 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top

Copyright © 2019 My Math Forum. All rights reserved.      