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May 14th, 2015, 08:31 AM   #1
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Question Trigonometry question in satellite communication

Hello everybody,

I need help in finding the right position on the globe of an observer that looks on a geosynchronous satellite (the ones that fly right above the equator line).

I know the position of the satellite, and the unit vector of the antenna pointing (azimuth and elevation) and I need to find latitude and longitude of the observer.

Here I have the reverse way. The knowns are the satellite position and latitude and longitude of the observer and the unknown is the unit vector or the way the antenna looks in relation with a tangent plane of the given position.
https://drive.google.com/openid=0B7D...X3c&authuser=0

I don't get the way they used the rotational matrix for transfering the values between the systems.

Here I have a representational picture:



Any help will be appreciated.

BR,
Andrian Buchi
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May 14th, 2015, 08:33 AM   #2
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Question Trigonometry problem for satellite communication

Hello everybody,

I need help in finding the right position on the globe of an observer that looks on a geosynchronous satellite (the ones that fly right above the equator line).

I know the position of the satellite, and the unit vector of the antenna pointing (azimuth and elevation) and I need to find latitude and longitude of the observer.

Here I have the reverse way. The knowns are the satellite position and latitude and longitude of the observer and the unknown is the unit vector or the way the antenna looks in relation with a tangent plane of the given position.
https://drive.google.com/openid=0B7D...X3c&authuser=0

I don't get the way they used the rotational matrix for transfering the values between the systems.

Here I have a representational picture:



Any help will be appreciated.

BR,
Andrian Buchi
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May 18th, 2015, 12:39 AM   #3
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I am unable to understand if you want to calculate the unit vector from the tangent at the observers coordinate to the position of the satellite. Then i think that the vector would always be perpendicular to this tangent plane.Pardon me if i am wrong.
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May 18th, 2015, 05:18 AM   #4
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Yes you're right about that.

But I'm looking for the observer position in latitude and longitude terms.
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