My Math Forum The anticlockwise angle a vector makes with the positive x axis

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 January 8th, 2015, 02:10 PM #1 Member   Joined: Sep 2014 From: UK Posts: 82 Thanks: 1 The anticlockwise angle a vector makes with the positive x axis I tried all possible answers and its says I'm wrong... vector b = 6i - 8j So I drew the angle and found its magnitude: I need to find the angle it makes with the positive x axis. I found the angle by Tan^-1(6/-8 ) = -37 (2sf) To find the angle it makes with the positive x axis, I thought it was 143 since id imagine it would be 180 - 37 = 143. But apparently it's not. Any help?
 January 8th, 2015, 05:18 PM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,723 Thanks: 1376 vector b = 6i - 8j is in quad IV, not quad II Thanks from Tangeton
January 8th, 2015, 10:39 PM   #3
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Math Focus: सामान्य गणित
your graph should look like this.
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 graph.jpg (35.6 KB, 0 views)

January 8th, 2015, 10:49 PM   #4
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Math Focus: सामान्य गणित
This graph shows the magnitude and direction of $\displaystyle \underset{i}{\rightarrow}$ and $\displaystyle \underset{j}{\rightarrow}$
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 component.jpg (17.2 KB, 2 views)

January 9th, 2015, 03:13 AM   #5
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Quote:
 Originally Posted by MATHEMATICIAN This graph shows the magnitude and direction of $\displaystyle \underset{i}{\rightarrow}$ and $\displaystyle \underset{j}{\rightarrow}$
Okay that makes sense! 360-53 = 307 anticlockwise from the positive x axis, it's right, thank you!

Last edited by Tangeton; January 9th, 2015 at 03:16 AM.

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