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January 8th, 2015, 02:10 PM  #1 
Member Joined: Sep 2014 From: UK Posts: 82 Thanks: 1  The anticlockwise angle a vector makes with the positive x axis
I tried all possible answers and its says I'm wrong... vector b = 6i  8j So I drew the angle and found its magnitude: I need to find the angle it makes with the positive x axis. I found the angle by Tan^1(6/8 ) = 37 (2sf) To find the angle it makes with the positive x axis, I thought it was 143 since id imagine it would be 180  37 = 143. But apparently it's not. Any help? 
January 8th, 2015, 05:18 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,836 Thanks: 1479 
vector b = 6i  8j is in quad IV, not quad II

January 8th, 2015, 10:39 PM  #3 
Math Team Joined: Jul 2013 From: काठमाडौं, नेपाल Posts: 879 Thanks: 60 Math Focus: सामान्य गणित 
your graph should look like this.

January 8th, 2015, 10:49 PM  #4 
Math Team Joined: Jul 2013 From: काठमाडौं, नेपाल Posts: 879 Thanks: 60 Math Focus: सामान्य गणित 
This graph shows the magnitude and direction of $\displaystyle \underset{i}{\rightarrow}$ and $\displaystyle \underset{j}{\rightarrow}$

January 9th, 2015, 03:13 AM  #5 
Member Joined: Sep 2014 From: UK Posts: 82 Thanks: 1  Okay that makes sense! 36053 = 307 anticlockwise from the positive x axis, it's right, thank you!
Last edited by Tangeton; January 9th, 2015 at 03:16 AM. 

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