January 5th, 2015, 11:29 PM  #1 
Newbie Joined: Jan 2015 From: canada Posts: 2 Thanks: 0  hydrobending setup
I'm trying to solve this seemingly simple equation said to be derived using Pythagoras theorem. I just can't seem to get the correct answer. If anyone could help explain how the sides were calculated, it would help me a lot! Need help ASAP! The final formula is: R = (l^2 + s^2)/(2s)  r  D/2 Last edited by skipjack; January 6th, 2015 at 04:35 PM. 
January 6th, 2015, 04:32 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 16,605 Thanks: 1201 
Was the original diagram that messy? It would help to know how the value of D is related to the other variables, but the formula doesn't look quite right anyway.

January 6th, 2015, 09:59 PM  #3 
Newbie Joined: Jan 2015 From: canada Posts: 2 Thanks: 0 
Nevermind  solved it thanks anyways! For anyone who is curious, a = l^2 b = R + D/2  (sr) c = R + D/2 + r Then use a^2 + b^2 = c^2 and solve for R. Last edited by skipjack; January 7th, 2015 at 12:39 AM. 
January 7th, 2015, 12:38 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 16,605 Thanks: 1201 
That method assumes that $OO_1 = R + D/2  (sr)$ and $OO_2 = R + D/2 + r$. It's not clear why those equations would hold, especially the first one. 

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