January 5th, 2015, 10:29 PM  #1 
Newbie Joined: Jan 2015 From: canada Posts: 2 Thanks: 0  hydrobending setup
I'm trying to solve this seemingly simple equation said to be derived using Pythagoras theorem. I just can't seem to get the correct answer. If anyone could help explain how the sides were calculated, it would help me a lot! Need help ASAP! The final formula is: R = (l^2 + s^2)/(2s)  r  D/2 Last edited by skipjack; January 6th, 2015 at 03:35 PM. 
January 6th, 2015, 03:32 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 17,702 Thanks: 1353 
Was the original diagram that messy? It would help to know how the value of D is related to the other variables, but the formula doesn't look quite right anyway.

January 6th, 2015, 08:59 PM  #3 
Newbie Joined: Jan 2015 From: canada Posts: 2 Thanks: 0 
Nevermind  solved it thanks anyways! For anyone who is curious, a = l^2 b = R + D/2  (sr) c = R + D/2 + r Then use a^2 + b^2 = c^2 and solve for R. Last edited by skipjack; January 6th, 2015 at 11:39 PM. 
January 6th, 2015, 11:38 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 17,702 Thanks: 1353 
That method assumes that $OO_1 = R + D/2  (sr)$ and $OO_2 = R + D/2 + r$. It's not clear why those equations would hold, especially the first one. 

Tags 
hydrobending, setup 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Understanding the setup for the probability that $Ax^2+Bx+C$  askhwhelp  Advanced Statistics  1  March 2nd, 2014 12:40 PM 
Algebra setup  Rfeynman16  Algebra  1  January 31st, 2014 12:37 PM 
Algebra setup  Rfeynman16  Algebra  3  January 2nd, 2014 12:53 PM 
Tricky Equation Setup  julian21  Algebra  1  March 23rd, 2010 09:02 PM 