My Math Forum hydro-bending setup

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January 5th, 2015, 10:29 PM   #1
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hydro-bending setup

I'm trying to solve this seemingly simple equation said to be derived using Pythagoras theorem. I just can't seem to get the correct answer. If anyone could help explain how the sides were calculated, it would help me a lot! Need help ASAP!

The final formula is:

R = (l^2 + s^2)/(2s) - r - D/2
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Last edited by skipjack; January 6th, 2015 at 03:35 PM.

 January 6th, 2015, 03:32 PM #2 Global Moderator   Joined: Dec 2006 Posts: 19,047 Thanks: 1618 Was the original diagram that messy? It would help to know how the value of D is related to the other variables, but the formula doesn't look quite right anyway.
 January 6th, 2015, 08:59 PM #3 Newbie   Joined: Jan 2015 From: canada Posts: 2 Thanks: 0 Nevermind - solved it thanks anyways! For anyone who is curious, a = l^2 b = R + D/2 - (s-r) c = R + D/2 + r Then use a^2 + b^2 = c^2 and solve for R. Last edited by skipjack; January 6th, 2015 at 11:39 PM.
 January 6th, 2015, 11:38 PM #4 Global Moderator   Joined: Dec 2006 Posts: 19,047 Thanks: 1618 That method assumes that $OO_1 = R + D/2 - (s-r)$ and $OO_2 = R + D/2 + r$. It's not clear why those equations would hold, especially the first one.

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