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January 5th, 2015, 10:29 PM   #1
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hydro-bending setup

I'm trying to solve this seemingly simple equation said to be derived using Pythagoras theorem. I just can't seem to get the correct answer. If anyone could help explain how the sides were calculated, it would help me a lot! Need help ASAP!

The final formula is:

R = (l^2 + s^2)/(2s) - r - D/2
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Last edited by skipjack; January 6th, 2015 at 03:35 PM.
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January 6th, 2015, 03:32 PM   #2
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Was the original diagram that messy? It would help to know how the value of D is related to the other variables, but the formula doesn't look quite right anyway.
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January 6th, 2015, 08:59 PM   #3
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Nevermind - solved it thanks anyways!
For anyone who is curious,
a = l^2
b = R + D/2 - (s-r)
c = R + D/2 + r

Then use a^2 + b^2 = c^2
and solve for R.

Last edited by skipjack; January 6th, 2015 at 11:39 PM.
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January 6th, 2015, 11:38 PM   #4
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That method assumes that $OO_1 = R + D/2 - (s-r)$ and $OO_2 = R + D/2 + r$.

It's not clear why those equations would hold, especially the first one.
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