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 May 17th, 2014, 11:17 AM #1 Senior Member   Joined: Nov 2013 Posts: 434 Thanks: 8 cos(arctan(-4/3)-arcsin(24/25)... cos(arctan(-4/3)-arcsin(24/25)...
 May 17th, 2014, 11:23 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,788 Thanks: 1037 Math Focus: Elementary mathematics and beyond Do you mean 1. cos(arctan(-4/3) - arcsin(24/25)) or 2. cos(arctan(-4/3)) - arcsin(24/25) ?
 May 17th, 2014, 11:45 AM #3 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,788 Thanks: 1037 Math Focus: Elementary mathematics and beyond Ok. It's probably 1. cos(arctan(-4/3) - arcsin(24/25)) = 3/5 * 7/25 - 4/5 * 24/25 = -3/5, using cos(a - b) = cos(a)cos(b) + sin(a)sin(b).

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### sin(arcsin 7/25 - arctg 4/3)

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