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May 17th, 2014, 11:17 AM  #1 
Senior Member Joined: Nov 2013 Posts: 432 Thanks: 7  cos(arctan(4/3)arcsin(24/25)...
cos(arctan(4/3)arcsin(24/25)...

May 17th, 2014, 11:23 AM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,599 Thanks: 941 Math Focus: Elementary mathematics and beyond 
Do you mean 1. cos(arctan(4/3)  arcsin(24/25)) or 2. cos(arctan(4/3))  arcsin(24/25) ? 
May 17th, 2014, 11:45 AM  #3 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,599 Thanks: 941 Math Focus: Elementary mathematics and beyond 
Ok. It's probably 1. cos(arctan(4/3)  arcsin(24/25)) = 3/5 * 7/25  4/5 * 24/25 = 3/5, using cos(a  b) = cos(a)cos(b) + sin(a)sin(b). 

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