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March 23rd, 2014, 03:23 AM  #1 
Member Joined: Sep 2013 Posts: 75 Thanks: 0  trig reduction simplification
(sin x . 1/cos x . sin 5 /{ (sin x/cos x) . cos 29 .sin 29 .(1/2)} = (4 sin 29 . cos 29)/(cos 29 . sin 29) = 4 I am lost how we simplified step 1 to get step 2 somewhere I can see that there is Sin 2x. 
March 23rd, 2014, 04:44 AM  #2 
Math Team Joined: Sep 2007 Posts: 2,409 Thanks: 6  Re: trig reduction simplification
It's kind of obvious, isn't it? You have in the numerator and in the denominator. They cancel. sin(5= sin(2(29))= 2sin(29)cos(29). 
March 23rd, 2014, 05:25 AM  #3 
Member Joined: Sep 2013 Posts: 75 Thanks: 0  Re: trig reduction simplification
what a relief!I just realized. Thank ya


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reduction, simplification, trig 
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