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March 23rd, 2014, 03:23 AM   #1
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trig reduction simplification

(sin x . 1/cos x . sin 5 /{ (sin x/cos x) . cos 29 .sin 29 .(1/2)}
= (4 sin 29 . cos 29)/(cos 29 . sin 29)
= 4
I am lost how we simplified step 1 to get step 2
somewhere I can see that there is Sin 2x.
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March 23rd, 2014, 04:44 AM   #2
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Re: trig reduction simplification

It's kind of obvious, isn't it? You have in the numerator
and in the denominator. They cancel.

sin(5= sin(2(29))= 2sin(29)cos(29).
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March 23rd, 2014, 05:25 AM   #3
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Re: trig reduction simplification

what a relief!I just realized. Thank ya
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