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 March 23rd, 2014, 03:23 AM #1 Member   Joined: Sep 2013 Posts: 75 Thanks: 0 trig reduction simplification (sin x . 1/cos x . sin 5 /{ (sin x/cos x) . cos 29 .sin 29 .(1/2)} = (4 sin 29 . cos 29)/(cos 29 . sin 29) = 4 I am lost how we simplified step 1 to get step 2 somewhere I can see that there is Sin 2x.
 March 23rd, 2014, 04:44 AM #2 Math Team   Joined: Sep 2007 Posts: 2,409 Thanks: 6 Re: trig reduction simplification It's kind of obvious, isn't it? You have $\left(sin(x)\right)\left(\frac{1}{cos(x)}\right)= \frac{sin(x)}{cos(x)}$ in the numerator and $\frac{sin(x)}{cos(x)}$ in the denominator. They cancel. sin(5= sin(2(29))= 2sin(29)cos(29).
 March 23rd, 2014, 05:25 AM #3 Member   Joined: Sep 2013 Posts: 75 Thanks: 0 Re: trig reduction simplification what a relief!I just realized. Thank ya

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