Trig IDENTITIES

mathatesme · January 9th, 2014, 12:47 PM

Can you help me simplify these two equations with DETAIL not just ANSWER

1. cosx(1+tan^2x)

2. sec^2x-1 divided by secx-1

greg1313 · January 9th, 2014, 12:53 PM

mathatesme · January 13th, 2014, 03:10 AM

Thank you so much! I really appreciate you and your time. !

greg1313 · January 13th, 2014, 05:20 AM

January 9th, 2014, 12:47 PM	#1
mathatesme Newbie Joined: Nov 2013 Posts: 5 Thanks: 0	Trig IDENTITIES Can you help me simplify these two equations with DETAIL not just ANSWER 1. cosx(1+tan^2x) 2. sec^2x-1 divided by secx-1
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January 9th, 2014, 12:53 PM	#2
greg1313 Global Moderator Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,517 Thanks: 910 Math Focus: Elementary mathematics and beyond	Re: Trig IDENTITIES $\cos x(1\,+\,\tan^2x)\,=\,\cos x\,+\,\frac{\sin^2x}{\cos x}\,=\,\frac{\cos^2x\,+\,\sin^2x}{\cos x}\,=\,\frac{1}{\cos x}\,=\,\sec x$ $\frac{\sec^2x\,-\,1}{\sec x\,-\,1}\,=\,\frac{(\sec x\,-\,1)(\sec x\,+\,1)}{\sec x\,-\,1}\,=\,\sec x\,+\,1$
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January 13th, 2014, 03:10 AM	#3
mathatesme Newbie Joined: Nov 2013 Posts: 5 Thanks: 0	Re: Trig IDENTITIES Thank you so much! I really appreciate you and your time. !
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January 13th, 2014, 05:20 AM	#4
greg1313 Global Moderator Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,517 Thanks: 910 Math Focus: Elementary mathematics and beyond	Re: Trig IDENTITIES $\cos x(1\,+\,\tan^2x)\,=\,\cos x\sec^2x\,=\,\sec x$
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