Reconcile 2 Trigonometric Indentities Hi All, I'm stuck on a particular problem set: Establish the validity (reconcile) of the following  (1+sin x)/cos x = cos x/(1sin x) I'm finding it difficult to walk from either left to right or right to left i.e. I cannot decompose into other identities that will lead me to the other side. I thought about expanding the left side to sec x + tan x but that leads me nowhere. I'm stuck!! Help!! Thanks 
just get both sides over a common denominator and it should be obvious. 
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Thanks @romsek @DarnItJimImAnEngineer. Making the denominator common amongst both and crossing out common terms does make it obvious. I also took another path; I split (1sin x) into (1sin^2x)/(1+sin x) on the right hand side. Then cos x/[(1sin^2x)/(1+sin x)] (using the identity cos^2x+ sin^2x =1) and one can simplify this to what's on the left = (1+sin x)/cos x 
Does that always work? 
$\displaystyle \frac{1+\sin x}{\cos x}\cdot\frac{1\sin x}{1\sin x}=\frac{1\sin^2x}{\cos x(1\sin x)}=\frac{\cos^2x}{\cos x(1\sin x)}=\frac{\cos x}{1\sin x}$ 
What exactly does that prove? 
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