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June 5th, 2019, 01:34 PM   #1
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In triangle XYZ, XY=6, angle X=60, and angle Y=70. Determine the values of XZ, YZ, & angle Z.


Last edited by skipjack; June 5th, 2019 at 08:42 PM.
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June 5th, 2019, 01:55 PM   #2
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this is a simple application of the law of sines
and a bit of basic geometry (what is the sum of the angles of a triangle?)

I have great faith that you can obtain the answer on your own!
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June 5th, 2019, 08:54 PM   #3
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As XZ/sin(Y) = XY/sin(Z) and sin(Z) = sin(X + Y) = sin(X)cos(Y) + cos(X)sin(Y),

XZ = XY sin(Y) /(sin(X)cos(Y) + cos(X)sin(Y)) = XY/(sin(X)cot(Y) + cos(X)).
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