June 5th, 2019, 01:34 PM  #1 
Member Joined: Jan 2019 From: tornto Posts: 48 Thanks: 0  triangle
In triangle XYZ, XY=6, angle X=60, and angle Y=70. Determine the values of XZ, YZ, & angle Z. PLEASE HELP. Last edited by skipjack; June 5th, 2019 at 08:42 PM. 
June 5th, 2019, 01:55 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,452 Thanks: 1337 
this is a simple application of the law of sines and a bit of basic geometry (what is the sum of the angles of a triangle?) I have great faith that you can obtain the answer on your own! 
June 5th, 2019, 08:54 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,746 Thanks: 2133 
As XZ/sin(Y) = XY/sin(Z) and sin(Z) = sin(X + Y) = sin(X)cos(Y) + cos(X)sin(Y), XZ = XY sin(Y) /(sin(X)cos(Y) + cos(X)sin(Y)) = XY/(sin(X)cot(Y) + cos(X)). 

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