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 June 5th, 2019, 01:34 PM #1 Member   Joined: Jan 2019 From: tornto Posts: 48 Thanks: 0 triangle In triangle XYZ, XY=6, angle X=60, and angle Y=70. Determine the values of XZ, YZ, & angle Z. PLEASE HELP. Last edited by skipjack; June 5th, 2019 at 08:42 PM.
 June 5th, 2019, 01:55 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,552 Thanks: 1402 this is a simple application of the law of sines and a bit of basic geometry (what is the sum of the angles of a triangle?) I have great faith that you can obtain the answer on your own! Thanks from topsquark
 June 5th, 2019, 08:54 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,969 Thanks: 2219 As XZ/sin(Y) = XY/sin(Z) and sin(Z) = sin(X + Y) = sin(X)cos(Y) + cos(X)sin(Y), XZ = XY sin(Y) /(sin(X)cos(Y) + cos(X)sin(Y)) = XY/(sin(X)cot(Y) + cos(X)).

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