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 May 24th, 2019, 02:14 PM #1 Member   Joined: Jan 2019 From: tornto Posts: 48 Thanks: 0 triangle State sinB, cosB, tanB as ratio for the following triangle: answer: soh cah toa sinB = O/H = 8/17 cosB= a/h= 15/17 tanB= o/a= 8/15 Please check answers. Thanks. Last edited by skipjack; May 24th, 2019 at 02:49 PM.
 May 24th, 2019, 02:52 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,969 Thanks: 2219 Which side is opposite $B$ in the diagram? Thanks from topsquark
May 24th, 2019, 08:12 PM   #3
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Quote:
 Originally Posted by skipjack Which side is opposite $B$ in the diagram?
Good catch. I would've told him he was right!

-Dan

 May 25th, 2019, 02:26 PM #4 Member   Joined: Jan 2019 From: tornto Posts: 48 Thanks: 0 okey here my answer please check if my answers correct sinB = o/h = 15/17 =. 015224549 cosB = a/h= 8/17 = 0.058251062 tanB = o/a =15/8 = 0.03273661
May 25th, 2019, 03:16 PM   #5
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 Originally Posted by yorkmanz okey here my answer please check if my answers correct sinB = o/h = 15/17 =. 015224549 cosB = a/h= 8/17 = 0.058251062 tanB = o/a =15/8 = 0.03273661
Correct!

-Dan

 May 27th, 2019, 10:43 PM #6 Member   Joined: Jan 2019 From: tornto Posts: 48 Thanks: 0 sinB = o/h = 15/17 = .882352941 cosB = a/h = 8/17 = .470588235 tanB = o/a =15/8 = 1.875 correct ?
May 27th, 2019, 10:43 PM   #7
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Quote:
 Originally Posted by topsquark Correct! -Dan
sinB = o/h = 15/17 = .882352941

cosB = a/h = 8/17 = .470588235

tanB = o/a =15/8 = 1.875

correct ?

 May 28th, 2019, 02:39 AM #8 Global Moderator   Joined: Dec 2006 Posts: 20,969 Thanks: 2219 Yes, but the question didn't require the fractions to be evaluated as decimals.
 May 28th, 2019, 02:33 PM #9 Member   Joined: Jan 2019 From: tornto Posts: 48 Thanks: 0 thanks
May 28th, 2019, 02:33 PM   #10
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Quote:
 Originally Posted by skipjack Yes, but the question didn't require the fractions to be evaluated as decimals.

Good eye, did not pay attention to that..

thanks

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