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March 21st, 2019, 07:34 PM  #1 
Newbie Joined: Mar 2019 From: Coldland Posts: 5 Thanks: 0  Trig Problem Question within a question
Problem says to find the Cosine and Sine of pi/6  Here is the question: As before, the terminal side of θ = pi/6 does not lie on any of the coordinate axes, so we proceed using a triangle approach. Letting P(x, y) denote the point on the terminal side of θ which lies on the Unit Circle, we drop a perpendicular line segment from P to the xaxis to form a 30◦ − 60◦ − 90◦ right triangle. After a bit of Geometry we find x = y sq. root 3 Now, the problem reads on but my question or better yet where I am stumped at is where it states " After a bit of Geometry ... " What is this geometry I am overthinking. Thank you. 
March 21st, 2019, 08:03 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,467 Thanks: 1342  
March 21st, 2019, 08:25 PM  #3 
Newbie Joined: Mar 2019 From: Coldland Posts: 5 Thanks: 0 
Hi romsek, I still don't follow. X = Y root 3 ? How did you do this. I'm just starting Trig 
March 21st, 2019, 08:33 PM  #4 
Newbie Joined: Mar 2019 From: Coldland Posts: 5 Thanks: 0 
nvm romsek I now do understand it. Thank you. 

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