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March 21st, 2019, 07:34 PM   #1
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Trig Problem Question within a question

Problem says to find the Cosine and Sine of pi/6

-----------------------------------------------------------------------------

Here is the question: As before, the terminal side of θ = pi/6
does not lie on any of the coordinate axes, so we proceed
using a triangle approach. Letting P(x, y) denote the point on the terminal side of θ which
lies on the Unit Circle, we drop a perpendicular line segment from P to the x-axis to form a
30◦ − 60◦ − 90◦
right triangle. After a bit of Geometry we find x = y sq. root 3

Now, the problem reads on but my question or better yet where I am stumped at is where it states " After a bit of Geometry ... " What is this geometry I am overthinking.

Thank you.
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March 21st, 2019, 08:03 PM   #2
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March 21st, 2019, 08:25 PM   #3
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Hi romsek,

I still don't follow. X = Y root 3 ?

How did you do this. I'm just starting Trig
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March 21st, 2019, 08:33 PM   #4
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nvm romsek I now do understand it.

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