My Math Forum Solving inverse trigonometric equation

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 August 12th, 2018, 08:58 PM #1 Senior Member     Joined: Jan 2012 Posts: 140 Thanks: 2 Solving inverse trigonometric equation Hello, If $\displaystyle \left [ \textrm{arccot} x \right ]+\left [ \cos^{-1}x \right ]=0$. where x is a non-negative real no. and [.] denotes the greatest integer function, then what will be complete set of values of x satisfying this equation? Thx.
 August 12th, 2018, 09:29 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,529 Thanks: 1389 what have you tried?
 August 13th, 2018, 08:16 AM #3 Senior Member     Joined: Jan 2012 Posts: 140 Thanks: 2 I think graphical approach..
August 13th, 2018, 09:09 AM   #4
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Quote:
 Originally Posted by happy21 I think graphical approach..
I kinda doubt you have actually tried this or you would see the answer is obvious. Why don't you go ahead and graph the expression and come back if you have further questions.

 August 13th, 2018, 09:19 AM #5 Senior Member     Joined: Jan 2012 Posts: 140 Thanks: 2 Yeah, now it's solved. Thanks. Last edited by skipjack; August 14th, 2018 at 12:24 AM.
August 13th, 2018, 10:23 AM   #6
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Quote:
 Originally Posted by happy21 Yeah, now it's solved. Thanks.
You should have obtained

$x \in (\cos(1),1]$

Last edited by skipjack; August 14th, 2018 at 12:24 AM.

August 13th, 2018, 11:02 AM   #7
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Quote:
 Originally Posted by romsek you should have obtained $x \in (\cos(1),1]$
I obtained (cot(1),1].

Thx.

August 13th, 2018, 01:30 PM   #8
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Quote:
 Originally Posted by happy21 I obtained (cot(1),1]. Thx.
you are correct.

I was using arctan(x).

 Tags equation, inverse, solving, trigonometric

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