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July 10th, 2018, 11:27 AM  #1 
Newbie Joined: Jul 2018 From: Cornwall Posts: 2 Thanks: 0  Sides of a triangle using ratios and area
Hello, I have a question that I cannot find the solution to and would be grateful for any help. A rightangled triangle has an area of 2.8m^2. The sides are in the ratio of 5:12:13 and the triangle stands on the shortest side. Calculate the following: a) the perpendicular height b) the hypotenuse again thank you for any help. Last edited by skipjack; July 10th, 2018 at 11:53 AM. 
July 10th, 2018, 11:53 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,978 Thanks: 788 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle 2.8 = \frac{1}{2} (5x)(12x)$ Solve this for x and then you can say what b = 5x and h = 12x are. Can you finish? Dan Last edited by skipjack; July 10th, 2018 at 11:59 AM.  
July 10th, 2018, 11:57 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,089 Thanks: 1902 
If the "perpendicular height" is 12y, the other sides have lengths 5y and 13y. What is the triangle's area in terms of y? Oh, topsquark posted much the same while I was typing!

July 10th, 2018, 12:19 PM  #4 
Newbie Joined: Jul 2018 From: Cornwall Posts: 2 Thanks: 0 
Thank you for your quick response. I can sleep easy now.
Last edited by skipjack; July 10th, 2018 at 12:48 PM. 

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area, ratios, sides, triangle 
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