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 June 6th, 2018, 02:59 AM #1 Newbie   Joined: Apr 2018 From: Banovo Brdo Posts: 12 Thanks: 0 Minimum of a function How do I find the minimum of this function? $f(x)=\frac{x^2}{8}+x\cos{x}+\cos2x$ Solution is -1. Thanks!
 June 6th, 2018, 08:15 AM #2 Global Moderator   Joined: Dec 2006 Posts: 19,722 Thanks: 1807 Hint: $x^2/8 + x\cos(x) + \cos(2x) = -1 + (x + 4\cos(x))^2/8$. Thanks from bongcloud

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