June 6th, 2018, 03:59 AM  #1 
Newbie Joined: Apr 2018 From: Banovo Brdo Posts: 12 Thanks: 0  Minimum of a function
How do I find the minimum of this function? $f(x)=\frac{x^2}{8}+x\cos{x}+\cos2x$ Solution is 1. Thanks! 
June 6th, 2018, 09:15 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,302 Thanks: 1974 
Hint: $x^2/8 + x\cos(x) + \cos(2x) = 1 + (x + 4\cos(x))^2/8$.


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