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June 3rd, 2018, 04:31 AM   #11
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Originally Posted by skipjack View Post
The question specifies a circle with AD as diameter. That circle is the circumcircle of triangle AEF, not triangle ABC.

As AD is a diameter of the circumcircle of triangle AEF, AD = EF/sin A is a consequence of the sine rule.

In the diagram below, the circumcircle of triangle ABC isn't shown, but its radius is R.
Attachment 9736
But $\displaystyle \Delta $ = area of $\triangle$ ABC..??

Last edited by skipjack; July 23rd, 2018 at 01:09 PM.
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July 23rd, 2018, 01:07 PM   #12
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I'm not sure what you meant by "It", but R is the circumradius of triangle ABC in the correct interpretation of the question.
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