May 31st, 2018, 12:50 PM  #1 
Newbie Joined: May 2018 From: Brazil Posts: 2 Thanks: 0  Transformations
Prove: 
May 31st, 2018, 02:26 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,285 Thanks: 1681 
Using $\sin4x + \sin2x = 2\sin3x\cos x \text{ and } \cos4x + \cos2x = 2\cos3x\cos x$, LHS = $\displaystyle \frac{(2\cos x  1)\sin3x}{(2\cos x  1)\cos3x} = \tan3x$. Last edited by skipjack; May 31st, 2018 at 06:22 PM. 
May 31st, 2018, 04:19 PM  #3 
Newbie Joined: May 2018 From: Brazil Posts: 2 Thanks: 0 
Thanks 

Tags 
transformations 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Transformations  Adrian  Algebra  20  March 6th, 2011 05:12 PM 
exp  log transformations  reto11  Applied Math  1  October 18th, 2010 10:08 PM 
Transformations  julian21  Algebra  4  July 17th, 2010 01:34 PM 
TRANSFORMATIONS PLEASE HELP  maigowai  Algebra  1  July 9th, 2010 12:49 AM 