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May 27th, 2018, 05:50 AM   #1
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Smallest Asymptote of a tan function

Hi guys. How does one go about finding the smallest asymptote of this function. f(x) = tan(-9x+8 ) where x>=0 (in radians)
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May 27th, 2018, 07:17 AM   #2
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For x = (8 - 5pi/2)/9, -9x + 8 = 5pi/2, and so tan(-9x + 8) is undefined. There's no asymptote closer to the origin (even if negative values of x are allowed).
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May 27th, 2018, 07:19 AM   #3
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where did you get the 5pi/2 from? or rather, where did you get the whole x equation from?
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May 27th, 2018, 11:29 AM   #4
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As -9x + 8 needs to be an odd multiple of pi/2, I selected the odd multiple of pi/2 that's closest to 8 and then found the corresponding value of x, which happened to be non-negative, as required.
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