April 16th, 2018, 11:05 AM  #1 
Newbie Joined: Apr 2018 From: East London Posts: 12 Thanks: 0  General Solution
Determine the General Solution 4cos^2 (x)  Sin (2x180)= tan^2 675 
April 16th, 2018, 01:09 PM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,159 Thanks: 878 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle \sin(2x  180) = \sin(2x)$ $\displaystyle \tan(675) = \tan(315) = \tan(45) = \tan(45) = 1$ So your equation is now $\displaystyle 4 \cos^2(x) + \sin(2x) = 1$ Can you finish? Dan Last edited by skipjack; April 16th, 2018 at 03:32 PM.  

Tags 
general, solution 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Getting the General solution  The_Ys_Guy  Differential Equations  10  April 19th, 2018 12:36 PM 
general solution  eulid  Differential Equations  1  November 26th, 2017 04:44 AM 
General solution  woo  Differential Equations  1  April 27th, 2015 04:51 PM 
General Solution  AzraaBux  Algebra  4  May 31st, 2013 07:13 AM 
General Solution of a PDE  mathbalarka  Calculus  11  May 5th, 2013 11:01 AM 