April 16th, 2018, 11:05 AM  #1 
Newbie Joined: Apr 2018 From: East London Posts: 12 Thanks: 0  General Solution
Determine the General Solution 4cos^2 (x)  Sin (2x180)= tan^2 675 
April 16th, 2018, 01:09 PM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,797 Thanks: 715 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle \sin(2x  180) = \sin(2x)$ $\displaystyle \tan(675) = \tan(315) = \tan(45) = \tan(45) = 1$ So your equation is now $\displaystyle 4 \cos^2(x) + \sin(2x) = 1$ Can you finish? Dan Last edited by skipjack; April 16th, 2018 at 03:32 PM.  

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