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 April 16th, 2018, 11:05 AM #1 Newbie   Joined: Apr 2018 From: East London Posts: 12 Thanks: 0 General Solution Determine the General Solution 4cos^2 (-x) - Sin (2x-180)= tan^2 675
April 16th, 2018, 01:09 PM   #2
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Quote:
 Originally Posted by Vee88 Determine the General Solution 4cos^2 (-x) - Sin (2x-180)= tan^2 675
$\displaystyle \cos(-x) = \cos(x)$

$\displaystyle \sin(2x - 180) = -\sin(2x)$

$\displaystyle \tan(675) = \tan(315) = \tan(-45) = -\tan(45) = -1$

$\displaystyle 4 \cos^2(x) + \sin(2x) = 1$

Can you finish?

-Dan

Last edited by skipjack; April 16th, 2018 at 03:32 PM.

 April 16th, 2018, 03:35 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,636 Thanks: 2080 Already solved here.

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