User Name Remember Me? Password

 Trigonometry Trigonometry Math Forum

 July 22nd, 2008, 04:33 PM #1 Newbie   Joined: Jul 2008 Posts: 10 Thanks: 0 Line tangent to a circle. The line 3x + 4y - 14 = 0 is tangent to the circle with center C ( -1, -2 ). How would you determine the radius of the circle algebraically? And write the equation of the circle? July 23rd, 2008, 01:13 AM #2 Newbie   Joined: Jun 2008 From: New Zealand Posts: 20 Thanks: 0 Re: Line tangent to a circle. The radius of the circle is equal to the distance from the center (-1, -2) to the line 3x + 4y - 14 = 0. The distance from $\displaystyle (x_0 , y_0)$ to line $\displaystyle Ax + By + C = 0$ can be found by the formula: $\displaystyle D = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}}$ Last edited by skipjack; February 28th, 2018 at 12:53 PM. Tags circle, line, tangent Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post lauchagonzalez Trigonometry 3 November 19th, 2013 11:40 AM Lucida Trigonometry 2 May 19th, 2012 01:01 AM snigdha Complex Analysis 5 April 17th, 2011 01:12 PM brian890 Trigonometry 3 March 4th, 2011 07:30 PM Lax Trigonometry 5 September 10th, 2008 03:28 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top      