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 February 28th, 2018, 03:00 AM #1 Newbie   Joined: Feb 2018 From: Diepenbeek, Limburg, Belgium Posts: 2 Thanks: 0 Simplify Trigonometric Quotient I have a hard time simplifying a math problem. (cosx+cos2x+cos3x) / (sinx+sin2x+sin3x) (and xeR) Can somebody help me out with this? Thanks!! Last edited by skipjack; February 28th, 2018 at 08:28 PM.
 February 28th, 2018, 04:55 PM #2 Global Moderator   Joined: May 2007 Posts: 6,807 Thanks: 717 Try reducing everything to combinations of sinx and cosx. Thanks from Fene
 February 28th, 2018, 07:22 PM #3 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond cot(2x), using the identities found here. Last edited by greg1313; February 28th, 2018 at 07:35 PM.
 February 28th, 2018, 08:25 PM #4 Global Moderator   Joined: Dec 2006 Posts: 20,942 Thanks: 2210 Code: cos(x) + cos(2x) + cos3x) cos(2x) + 2cos(2x)cos(x) ------------------------- = ------------------------- = cot(2x) sin(x) + sin(2x) + sin(3x) sin(2x) + 2sin(2x)cos(x) Thanks from Fene

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