October 22nd, 2017, 06:21 PM  #1 
Newbie Joined: Oct 2017 From: Redlands, CA Posts: 15 Thanks: 0  Trig Identities Question
Could someone please explain to me how: 16(sin^2 theta) = 15 (sin^2 theta) + sin ^2 theta I know it has to do with an algebraic manipulation using the Pythagorean identity of: sin^2 theta + cos^2 theta = 1 But I just can't wrap my head around what happens to get the extra sin^2 theta. Thanks in advance for your help. Last edited by skipjack; October 22nd, 2017 at 07:18 PM. 
October 22nd, 2017, 06:55 PM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,723 Thanks: 985 Math Focus: Elementary mathematics and beyond 
16 = 15 + 1

October 22nd, 2017, 09:15 PM  #3 
Newbie Joined: Oct 2017 From: Redlands, CA Posts: 15 Thanks: 0  Ohhh... 15x+1x=16x Thanks. I was completely overthinking it. 

Tags 
identities, question, trig 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
another trig identities question  harissia  Trigonometry  3  November 16th, 2015 09:15 AM 
Trig Identities question  harissia  Trigonometry  3  November 15th, 2015 01:31 PM 
question about identities for integrating trig functions  cheyb93  Calculus  1  March 1st, 2013 09:45 PM 
Trig Identities  One Question Please Help!  jmhelp  Trigonometry  4  May 26th, 2011 09:23 PM 
Trig identities question...  xosarah  Algebra  1  April 17th, 2010 06:09 AM 