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October 22nd, 2017, 06:21 PM   #1
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Trig Identities Question

Could someone please explain to me how:

16(sin^2 theta) = 15 (sin^2 theta) + sin ^2 theta

I know it has to do with an algebraic manipulation using the Pythagorean identity of: sin^2 theta + cos^2 theta = 1

But I just can't wrap my head around what happens to get the extra sin^2 theta.

Thanks in advance for your help.

Last edited by skipjack; October 22nd, 2017 at 07:18 PM.
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October 22nd, 2017, 06:55 PM   #2
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16 = 15 + 1
Thanks from topsquark and JPow
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October 22nd, 2017, 09:15 PM   #3
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Ohhh... 15x+1x=16x

Thanks. I was completely overthinking it.
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