October 22nd, 2017, 05:21 PM  #1 
Newbie Joined: Oct 2017 From: Redlands, CA Posts: 15 Thanks: 0  Trig Identities Question
Could someone please explain to me how: 16(sin^2 theta) = 15 (sin^2 theta) + sin ^2 theta I know it has to do with an algebraic manipulation using the Pythagorean identity of: sin^2 theta + cos^2 theta = 1 But I just can't wrap my head around what happens to get the extra sin^2 theta. Thanks in advance for your help. Last edited by skipjack; October 22nd, 2017 at 06:18 PM. 
October 22nd, 2017, 05:55 PM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,805 Thanks: 1045 Math Focus: Elementary mathematics and beyond 
16 = 15 + 1

October 22nd, 2017, 08:15 PM  #3 
Newbie Joined: Oct 2017 From: Redlands, CA Posts: 15 Thanks: 0  Ohhh... 15x+1x=16x Thanks. I was completely overthinking it. 

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