June 28th, 2017, 05:40 AM  #1 
Newbie Joined: Jun 2017 From: Serbia Posts: 3 Thanks: 0  Find the domain
f(x)=sqrtsin(cosx) Im very confused. 
June 28th, 2017, 06:26 AM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,476 Thanks: 495 Math Focus: Yet to find out. 
Maybe elaborate on your confusion.

June 28th, 2017, 07:01 AM  #3 
Newbie Joined: Jun 2017 From: Serbia Posts: 3 Thanks: 0 
Cosx needs to have positive value so sin(cosx) is greater or eqal to 0 ? But if cosx is for example 1/2, how can i find sin1/2 if thats not an angle but a number?
Last edited by Guiless; June 28th, 2017 at 07:04 AM. 
June 28th, 2017, 07:04 AM  #4 
Senior Member Joined: Dec 2012 From: Hong Kong Posts: 853 Thanks: 311 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics  
June 28th, 2017, 07:41 AM  #5 
Math Team Joined: Jul 2011 From: Texas Posts: 2,692 Thanks: 1351 
$f(x) = \sqrt{\sin(\cos{x})}$ note $1 \le \cos{x} \le 1 \implies \sin(\cos{x}) \ge 0$ for $0 \le \cos{x} \le 1$ $0 \le \cos{x} \le 1$ for values of $x$ in quadrants I and IV $\dfrac{\pi}{2} + 2k\pi \le x \le \dfrac{\pi}{2} + 2k\pi$, $k \in \mathbb{Z}$ 
June 28th, 2017, 09:16 AM  #6 
Newbie Joined: Jun 2017 From: Serbia Posts: 3 Thanks: 0 
Thank you ive got it.


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