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 June 28th, 2017, 04:40 AM #1 Newbie   Joined: Jun 2017 From: Serbia Posts: 3 Thanks: 0 Find the domain f(x)=sqrtsin(cosx) Im very confused. June 28th, 2017, 05:26 AM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,843 Thanks: 657 Math Focus: Yet to find out. Maybe elaborate on your confusion. Thanks from 123qwerty June 28th, 2017, 06:01 AM #3 Newbie   Joined: Jun 2017 From: Serbia Posts: 3 Thanks: 0 Cosx needs to have positive value so sin(cosx) is greater or eqal to 0 ? But if cosx is for example 1/2, how can i find sin1/2 if thats not an angle but a number? Last edited by Guiless; June 28th, 2017 at 06:04 AM. June 28th, 2017, 06:04 AM   #4
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 Originally Posted by Guiless Cosx needs to have positive value so sin(cosx) is greater or eqal to 0 ? But if cosx is for example 1/2, how can i find sin1/2 if thats not an angle but a mumber?
Just treat the $\displaystyle \frac{1}{2}$ as if it were in radians. June 28th, 2017, 06:41 AM #5 Math Team   Joined: Jul 2011 From: Texas Posts: 3,044 Thanks: 1627 $f(x) = \sqrt{\sin(\cos{x})}$ note $-1 \le \cos{x} \le 1 \implies \sin(\cos{x}) \ge 0$ for $0 \le \cos{x} \le 1$ $0 \le \cos{x} \le 1$ for values of $x$ in quadrants I and IV $-\dfrac{\pi}{2} + 2k\pi \le x \le \dfrac{\pi}{2} + 2k\pi$, $k \in \mathbb{Z}$ June 28th, 2017, 08:16 AM #6 Newbie   Joined: Jun 2017 From: Serbia Posts: 3 Thanks: 0 Thank you ive got it. Tags domain, find Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post alexpasty Algebra 2 January 8th, 2014 05:51 AM Shamieh Algebra 4 April 30th, 2013 08:59 PM alloy Algebra 4 October 30th, 2012 09:45 AM symmetry Algebra 6 June 5th, 2007 06:34 AM Shamieh Calculus 3 December 31st, 1969 04:00 PM

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