Find the domain f(x)=sqrtsin(cosx) Im very confused. 
Maybe elaborate on your confusion. 
Cosx needs to have positive value so sin(cosx) is greater or eqal to 0 ? But if cosx is for example 1/2, how can i find sin1/2 if thats not an angle but a number? 
Quote:

$f(x) = \sqrt{\sin(\cos{x})}$ note $1 \le \cos{x} \le 1 \implies \sin(\cos{x}) \ge 0$ for $0 \le \cos{x} \le 1$ $0 \le \cos{x} \le 1$ for values of $x$ in quadrants I and IV $\dfrac{\pi}{2} + 2k\pi \le x \le \dfrac{\pi}{2} + 2k\pi$, $k \in \mathbb{Z}$ 
Thank you ive got it. 
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