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 June 23rd, 2017, 08:15 AM #1 Senior Member   Joined: Aug 2014 From: Mars Posts: 101 Thanks: 9 Isosceles triangle? Picture an isosceles triangle with two sides 8 and a base of 6. Is it equal to Sec $\frac{4}{3}$ Or what is it equal to?
 June 23rd, 2017, 08:35 AM #2 Senior Member   Joined: Dec 2012 From: Hong Kong Posts: 853 Thanks: 311 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics What does 'it' refer to?
 June 23rd, 2017, 08:53 AM #3 Senior Member   Joined: Aug 2014 From: Mars Posts: 101 Thanks: 9 I don't know. The question was given without context. It was multiple choice and the four options were(I think)... $Cos$ 1 $Tan$ 1 $Sec \frac{4}{3}$ $Sec \frac{3}{4}$ If none of these work, then my memory is faulty. Let me know what you think the answer is. And what section of trigonometry it is so I can study it.
 June 23rd, 2017, 09:30 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,941 Thanks: 2210 Do you have any information about the origin of the question?
June 24th, 2017, 12:21 AM   #5
Senior Member

Joined: Aug 2014
From: Mars

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Quote:
 Originally Posted by skipjack Do you have any information about the origin of the question?
It was from an accuplacer test.

There was a photo of two sides equaling 8 and the base equaling 6. Then the four options I listed. Or similar.

 June 24th, 2017, 04:19 AM #6 Math Team     Joined: Jul 2011 From: Texas Posts: 3,005 Thanks: 1588 did you know that eyewitness testimony is seldom reliable because of missing details? the answer choices you think you saw make no sense w/regard to the isosceles triangle described. the two congruent base angles each have measure $\cos^{-1}\left(\dfrac{3}{8}\right) = \sec^{-1}\left(\dfrac{8}{3}\right)$ the vertex angle between the two equal legs has measure $2\sin^{-1}\left(\dfrac{3}{8}\right)$

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