June 23rd, 2017, 08:15 AM  #1 
Member Joined: Aug 2014 From: Mars Posts: 88 Thanks: 8  Isosceles triangle?
Picture an isosceles triangle with two sides 8 and a base of 6. Is it equal to Sec $\frac{4}{3}$ Or what is it equal to? 
June 23rd, 2017, 08:35 AM  #2 
Senior Member Joined: Dec 2012 From: Hong Kong Posts: 849 Thanks: 307 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics 
What does 'it' refer to? 
June 23rd, 2017, 08:53 AM  #3 
Member Joined: Aug 2014 From: Mars Posts: 88 Thanks: 8 
I don't know. The question was given without context. It was multiple choice and the four options were(I think)... $Cos$ 1 $Tan$ 1 $Sec \frac{4}{3}$ $Sec \frac{3}{4}$ If none of these work, then my memory is faulty. Let me know what you think the answer is. And what section of trigonometry it is so I can study it. 
June 23rd, 2017, 09:30 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 17,466 Thanks: 1312 
Do you have any information about the origin of the question?

June 24th, 2017, 12:21 AM  #5 
Member Joined: Aug 2014 From: Mars Posts: 88 Thanks: 8  
June 24th, 2017, 04:19 AM  #6 
Math Team Joined: Jul 2011 From: Texas Posts: 2,569 Thanks: 1272 
did you know that eyewitness testimony is seldom reliable because of missing details? the answer choices you think you saw make no sense w/regard to the isosceles triangle described. the two congruent base angles each have measure $\cos^{1}\left(\dfrac{3}{8}\right) = \sec^{1}\left(\dfrac{8}{3}\right)$ the vertex angle between the two equal legs has measure $2\sin^{1}\left(\dfrac{3}{8}\right)$ 

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