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June 23rd, 2017, 08:15 AM   #1
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Isosceles triangle?

Picture an isosceles triangle with two sides 8 and a base of 6. Is it equal to

Sec $\frac{4}{3}$


Or what is it equal to?
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June 23rd, 2017, 08:35 AM   #2
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What does 'it' refer to?
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June 23rd, 2017, 08:53 AM   #3
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I don't know. The question was given without context. It was multiple choice and the four options were(I think)...

$Cos$ 1
$Tan$ 1
$Sec \frac{4}{3}$
$Sec \frac{3}{4}$


If none of these work, then my memory is faulty. Let me know what you think the answer is. And what section of trigonometry it is so I can study it.
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June 23rd, 2017, 09:30 AM   #4
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Do you have any information about the origin of the question?
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June 24th, 2017, 12:21 AM   #5
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Quote:
Originally Posted by skipjack View Post
Do you have any information about the origin of the question?
It was from an accuplacer test.

There was a photo of two sides equaling 8 and the base equaling 6. Then the four options I listed. Or similar.
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June 24th, 2017, 04:19 AM   #6
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did you know that eyewitness testimony is seldom reliable because of missing details?

the answer choices you think you saw make no sense w/regard to the isosceles triangle described.

the two congruent base angles each have measure $\cos^{-1}\left(\dfrac{3}{8}\right) = \sec^{-1}\left(\dfrac{8}{3}\right)$

the vertex angle between the two equal legs has measure $2\sin^{-1}\left(\dfrac{3}{8}\right)$
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