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February 23rd, 2017, 05:04 AM  #1 
Newbie Joined: Nov 2016 From: London Posts: 7 Thanks: 0  questions involving double angles
Hello everyone... again I've been given a couple of questions and I have no flipping idea how to do them. The teacher has been over double angle identities with us but the following questions have left me stumped, even with all my notes and textbook out. so here it is: Solve the equation $\sqrt{3}\cos2x\sin x \cos x1=0 \\ 0\leq{x}\leq360^{\circ}$ The main problem here is that I'm not quite sure how to simplify it. Thanks for reading! Looking forward to some enlightenment. Last edited by skipjack; February 23rd, 2017 at 05:52 AM. 
February 23rd, 2017, 05:58 AM  #2 
Senior Member Joined: Sep 2015 From: CA Posts: 1,238 Thanks: 637 
Is it possibly $\dfrac{\sqrt{3}}{2}\cos(2x)  \sin(x)\cos(x)1=0$?
Last edited by skipjack; February 23rd, 2017 at 06:11 AM. 
February 23rd, 2017, 02:23 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,235 Thanks: 497 
Start with sinxcosx=(sin2x)/2. Try solving for 2x.


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