
Trigonometry Trigonometry Math Forum 
 LinkBack  Thread Tools  Display Modes 
January 5th, 2017, 11:54 AM  #1 
Newbie Joined: Jan 2017 From: Irvine California Posts: 3 Thanks: 0  composite argument properties
sin(a+b) = sin(a)cos(b) + cos(a)sin(b) Of course there are more for cos etc. I am wondering if any of you fine gentlemen or ladies have any information on the history of this property: I.E: who discovered it and perhaps a location of their notes? I am also in search of a concise proof; that search is possible through google though if you happen to know of a location for such a thing a url or search term is appreciated. Buffalo 
January 5th, 2017, 12:08 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,197 Thanks: 1048  
January 5th, 2017, 03:56 PM  #3 
Member Joined: Sep 2016 From: USA Posts: 98 Thanks: 36 Math Focus: Dynamical systems, analytic function theory, numerics 
I doubt anyone knows who discovered this and I'm sure it was known long before it was rigorously proved. The most concise proof (also what I believe to be the "best" proof) is the following: For any $x \in \mathbb{R}$, we have $e^{ix} = \cos x + i \sin x$. It follows that for $a,b \in \mathbb{R}$ we have $$\sin(a+b) = \Im (e^{i(a+b)}) = \Im(e^{ia}e^{ib}) = \Im ((\cos a + i \sin a)(\cos b + i \sin b)) = \cos a \sin b + \cos b \sin a$$. The proof for $\cos(a+b)$ follows similarly by taking the real part. The magic of this computation is its so obvious once you've seen it that you never have to memorize these identities again. In fact, similar computations replace almost all of the trig identities you had to memorize as an undergrad. 
January 7th, 2017, 11:56 PM  #4 
Newbie Joined: Jan 2017 From: Irvine California Posts: 3 Thanks: 0 
Thank you both for your responses. However, skeeter yours certainly proves the relationships, but it seems so contrived and what I am searching for and will benefit from is learning exactly how a mind could complicate a formula so simple to Code: (cos α − cos β)^2 + (sin α − sin β)^2 = (cos(α − β) − 1)^2 + (sin(α − β) − 0)^2 SDK, your proof seems like it may bear fruit in that very regard. Unfortunately I lack the level of mathematical nomenclature knowledge to fully grasp what you have written. I am trying to use the powers of the internet to decode your proof, however, the nature of it still eludes me. Perhaps, and I am sure you are busy and could spend your time carrying on more important tasks, you could explain. 
January 8th, 2017, 01:51 AM  #5  
Senior Member Joined: Aug 2012 Posts: 859 Thanks: 160  Quote:
The key is Euler's formula. If $x$ is any real number, then $e^{ix} = \cos x + i \sin x$. This is really an amazing fact. It's the key that relates trigonometry to the complex numbers and the complex exponential function. Then if $a$ and $b$ are real numbers we have $e^{i(a + b)} = \cos (a + b) + i \sin (a + b)$  Call this equation (1) On the other hand from the rules for exponents (which are valid for complex numbers as well as real numbers, something that needs proof), we have $e^{i(a + b)} = e^{ai + bi} = e^{ai} e^{bi}$ $= (\cos a + i \sin a)(\cos b + i \sin b)$  Euler's formula twice $= \cos a \cos b  \sin a \sin b + i(\cos a \sin b + \sin a \cos b)$  Call this equation (2) (The last line comes from multiplying out the two binomials in the prior line and applying the relation $i^2 = 1$). Now equating the respective real and imaginary parts of equations (1) and (2) gives $\cos (a + b) = \cos a \cos b  \sin a \sin b$ and $\sin (a + b) = \cos a \sin b + \sin a \cos b$ and as SDK notes, you never have to memorize these identities again. You just run through this little calculation whenever you need them. <MathEdRant> For this and many other reasons, high school trig should be taught based on the complex numbers, making life so much simpler. We don't use trig to measure the fields we're farming like we did a thousand years ago. Trig is not about triangles, it's about the unit circle. We care about $\sin$ and $\cos$ because they're the building blocks of Fourier series and modern digital signal processing. Math education needs to catch up. </MathEdRant> Last edited by Maschke; January 8th, 2017 at 02:02 AM.  

Tags 
argument, composite, properties 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Composite for ever  mobel  Number Theory  2  July 8th, 2016 07:14 AM 
n!*(n+1)!  1 composite?  Bogauss  Number Theory  26  February 21st, 2011 01:29 PM 
[SOLVED] Composite argument property  please help!  homer  Algebra  1  July 23rd, 2010 04:19 AM 
Composite of f, g, and/or h.  symmetry  Algebra  1  June 12th, 2007 09:07 PM 
[SOLVED] Composite argument property  please help!  homer  Calculus  1  January 1st, 1970 12:00 AM 