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December 10th, 2016, 03:48 PM   #1
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Solving a triangle

For the problem in the link below, I need to find the exact value of angle "A" so I used Pythagorean Theorem to get $\displaystyle \frac{12}{\sqrt{160}}$

How is the answer $\displaystyle \frac{\sqrt{10}}{3}$?

Last edited by haleywyn; December 10th, 2016 at 03:54 PM.
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December 10th, 2016, 03:56 PM   #2
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Originally Posted by haleywyn View Post
In the picture attached, I need to find the exact value of angle A, and I used the Pythagorean theorem to get
so I don't understand the correct answer.
You almost have it right. The hypotenuse is $\displaystyle \sqrt{4^2 + 12^2} = \sqrt{160}$. And we know that $\displaystyle csc(A) = \frac{1}{sin(A)} = \frac{\sqrt{160}}{12}$.

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solving, triangle

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