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December 9th, 2016, 07:50 AM   #1
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hi

Hello, can someone explain me this: tanβ=k ,
sinβ+k*cosβ=1/√(1+k²)+k²√(1+k²)
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December 9th, 2016, 08:22 AM   #2
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sin b = 1/cosec b
= 1/sqrt(1+ cot square (b))
= tan b/sqrt(1+ tan square (b))
=k/sqrt(1 + k square)

cos b = 1/sec b
= 1/sqrt(1+ tan square (b))
= 1/sqrt(1 + k square)
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