December 9th, 2016, 06:50 AM |
#1 |

Newbie Joined: May 2016 From: serbia Posts: 4 Thanks: 0 | hi
Hello, can someone explain me this: tanβ=k , sinβ+k*cosβ=1/√(1+k²)+k²√(1+k²) |

December 9th, 2016, 07:22 AM |
#2 |

Newbie Joined: Nov 2016 From: Canada Posts: 13 Thanks: 3 Math Focus: All |
sin b = 1/cosec b = 1/sqrt(1+ cot square (b)) = tan b/sqrt(1+ tan square (b)) =k/sqrt(1 + k square) cos b = 1/sec b = 1/sqrt(1+ tan square (b)) = 1/sqrt(1 + k square) |