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December 5th, 2016, 11:52 PM   #1
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trig function question 2

Rachel is bowling with her friends. Her bowling ball has a radius of 4.3 inches. As she bowls, she tracks the location of the finger hole above the ground. She starts tracking the location when the finger hole is at the 12 o'clock position and she notices that she got some backspin on the ball and it rotates counter-clockwise.

The finger hole changes by 45 degrees.

Define a function, f, that gives the height of the finger hole above the ground (in inches) in terms of the angle of rotation (measured in radians) it has swept out from the 12 o'clock position, a.

Last edited by skipjack; December 6th, 2016 at 08:38 AM.
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December 6th, 2016, 03:34 AM   #2
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$0 \le \theta \le \dfrac{\pi}{4}$

$f(\theta) = r(1+\cos{\theta})$ where $r$ is the radius of the ball.
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December 6th, 2016, 09:05 AM   #3
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For swept angle $\theta$, where $\theta \in\hspace{1px}$[0, $\pi/4$], the hole has height given by f$(\theta) = 4.3(1 + \cos(\theta))$ inches.
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