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December 4th, 2016, 05:35 PM   #11
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Quote:
 Originally Posted by HisNameForever I did graph my attempt. Let me check the second part. No, it doesn't! What did I do wrong?
too much "C" and in the wrong direction.

Last edited by skeeter; December 4th, 2016 at 05:45 PM.

 December 4th, 2016, 07:45 PM #12 Newbie   Joined: Dec 2016 From: Oregon Posts: 8 Thanks: 0 Final Correct Solution P(t)=25sin(pi/12(t-6))+95 is correct. When you do P(12) It equals 120. My question is how did you immediately know that -6 shifted the graph correctly and that -6 was c? Thanks for your help. Last edited by HisNameForever; December 4th, 2016 at 08:01 PM.
December 4th, 2016, 08:19 PM   #13
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The green graph is the sine curve with no shift ... note the red curve is that green sine curve shifted right 6 hours.

btw ... the equation of the red curve can also be written $P(t)=95-25\cos\left(\dfrac{\pi}{12} \cdot t \right)$
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