Periodic Function - Page 2

skeeter · December 4th, 2016, 05:35 PM

Quote:

Originally Posted by HisNameForever $View Post$

I did graph my attempt. Let me check the second part. No, it doesn't! What did I do wrong?

too much "C" and in the wrong direction.

HisNameForever · December 4th, 2016, 07:45 PM

P(t)=25sin(pi/12(t-6))+95 is correct. When you do P(12) It equals 120. My question is how did you immediately know that -6 shifted the graph correctly and that -6 was c?

Thanks for your help.

skeeter · December 4th, 2016, 08:19 PM

The green graph is the sine curve with no shift ... note the red curve is that green sine curve shifted right 6 hours.

btw ... the equation of the red curve can also be written $P(t)=95-25\cos\left(\dfrac{\pi}{12} \cdot t \right)$

December 4th, 2016, 07:45 PM	#12
HisNameForever Newbie Joined: Dec 2016 From: Oregon Posts: 8 Thanks: 0	Final Correct Solution P(t)=25sin(pi/12(t-6))+95 is correct. When you do P(12) It equals 120. My question is how did you immediately know that -6 shifted the graph correctly and that -6 was c? Thanks for your help. Last edited by HisNameForever; December 4th, 2016 at 08:01 PM.
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