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 Trigonometry Trigonometry Math Forum

 October 27th, 2016, 09:51 AM #1 Newbie   Joined: Oct 2016 From: Rainfall Posts: 2 Thanks: 0 How to figure out the exact values? I'm wondering how to solve problems like this: Sin^-1(sin(90)) Can anyone help me with this? October 27th, 2016, 09:54 AM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 3,016 Thanks: 1600 I assume the 90 is in degrees ... $\sin^{-1}[\sin(90^\circ)] = \sin^{-1}(1) = 90^\circ$ October 27th, 2016, 10:18 AM #3 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,683 Thanks: 2664 Math Focus: Mainly analysis and algebra If $x=\sin^{-1} \big( \sin 90^\circ \big)$ then $\sin x=\sin 90^\circ$ October 27th, 2016, 10:25 AM #4 Newbie   Joined: Oct 2016 From: Rainfall Posts: 2 Thanks: 0 What if it were sin^-1(sin(180)) or cos^-1(sin(330))? October 27th, 2016, 11:39 AM #5 Math Team   Joined: Jul 2011 From: Texas Posts: 3,016 Thanks: 1600 I had a feeling this was going to be asked next ... $\sin^{-1}[\sin(180^\circ)] = \sin^{-1}(0) = 0$, because the range of the inverse sine function is $[-90^\circ, 90^\circ]$ $\cos^{-1}[\sin(330^\circ)] = \cos^{-1}\left(-\dfrac{1}{2}\right) = 120^\circ$ because the range of the inverse cosine function is $[0^\circ , 180^\circ]$ Thanks from topsquark Tags exact, figure, values Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Pete23 Trigonometry 6 August 3rd, 2016 06:42 PM alishab Trigonometry 8 December 11th, 2015 06:31 PM Qutyberry Trigonometry 8 May 3rd, 2014 08:32 PM gretchen Algebra 1 April 1st, 2007 01:01 AM hatcher777 Algebra 12 January 13th, 2007 03:43 AM

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