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April 17th, 2016, 01:46 PM  #1 
Senior Member Joined: Oct 2014 From: Complex Field Posts: 119 Thanks: 4  Getting one expression to another
Hello, I have the following expression: 1/((sinx)^2)  4/3, and I want to get to the following expression: 1/((tgx)^2)  1/3. I wasn't able to find the right identities, maybe you could help? Thanks! 
April 17th, 2016, 02:10 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,737 Thanks: 1387 
$\dfrac{1}{\sin^2{x}}  1  \dfrac{1}{3}$ $(\csc^2{x}  1)  \dfrac{1}{3}$ $\cot^2{x}  \dfrac{1}{3}$ $\dfrac{1}{\tan^2{x}}  \dfrac{1}{3}$ 
April 17th, 2016, 05:55 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 18,852 Thanks: 1570 
1/sin²x  4/3 = (cos²x + sin²x)/sin²x  4/3 = cos²x/sin²x + 1  4/3 = 1/tan²x  1/3

April 18th, 2016, 08:07 AM  #4 
Senior Member Joined: Oct 2014 From: Complex Field Posts: 119 Thanks: 4 
Thanks guys!!! Even got 2 options The more the merrier 

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