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 April 17th, 2016, 02:46 PM #1 Senior Member   Joined: Oct 2014 From: Complex Field Posts: 119 Thanks: 4 Getting one expression to another Hello, I have the following expression: 1/((sinx)^2) - 4/3, and I want to get to the following expression: 1/((tgx)^2) - 1/3. I wasn't able to find the right identities, maybe you could help? Thanks!
 April 17th, 2016, 03:10 PM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,815 Thanks: 1458 $\dfrac{1}{\sin^2{x}} - 1 - \dfrac{1}{3}$ $(\csc^2{x} - 1) - \dfrac{1}{3}$ $\cot^2{x} - \dfrac{1}{3}$ $\dfrac{1}{\tan^2{x}} - \dfrac{1}{3}$ Thanks from noobinmath
 April 17th, 2016, 06:55 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,264 Thanks: 1959 1/sin²x - 4/3 = (cos²x + sin²x)/sin²x - 4/3 = cos²x/sin²x + 1 - 4/3 = 1/tan²x - 1/3 Thanks from noobinmath
 April 18th, 2016, 09:07 AM #4 Senior Member   Joined: Oct 2014 From: Complex Field Posts: 119 Thanks: 4 Thanks guys!!! Even got 2 options The more the merrier

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