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April 17th, 2016, 02:46 PM | #1 |
Senior Member Joined: Oct 2014 From: Complex Field Posts: 119 Thanks: 4 | Getting one expression to another
Hello, I have the following expression: 1/((sinx)^2) - 4/3, and I want to get to the following expression: 1/((tgx)^2) - 1/3. I wasn't able to find the right identities, maybe you could help? Thanks! |
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April 17th, 2016, 03:10 PM | #2 |
Math Team Joined: Jul 2011 From: Texas Posts: 2,815 Thanks: 1458 |
$\dfrac{1}{\sin^2{x}} - 1 - \dfrac{1}{3}$ $(\csc^2{x} - 1) - \dfrac{1}{3}$ $\cot^2{x} - \dfrac{1}{3}$ $\dfrac{1}{\tan^2{x}} - \dfrac{1}{3}$ |
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April 17th, 2016, 06:55 PM | #3 |
Global Moderator Joined: Dec 2006 Posts: 20,264 Thanks: 1959 |
1/sin²x - 4/3 = (cos²x + sin²x)/sin²x - 4/3 = cos²x/sin²x + 1 - 4/3 = 1/tan²x - 1/3
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April 18th, 2016, 09:07 AM | #4 |
Senior Member Joined: Oct 2014 From: Complex Field Posts: 119 Thanks: 4 |
Thanks guys!!! Even got 2 options ![]() ![]() |
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