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- - **Getting one expression to another**
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Getting one expression to anotherHello, I have the following expression: 1/((sinx)^2) - 4/3, and I want to get to the following expression: 1/((tgx)^2) - 1/3. I wasn't able to find the right identities, maybe you could help? Thanks! |

$\dfrac{1}{\sin^2{x}} - 1 - \dfrac{1}{3}$ $(\csc^2{x} - 1) - \dfrac{1}{3}$ $\cot^2{x} - \dfrac{1}{3}$ $\dfrac{1}{\tan^2{x}} - \dfrac{1}{3}$ |

1/sin²x - 4/3 = (cos²x + sin²x)/sin²x - 4/3 = cos²x/sin²x + 1 - 4/3 = 1/tan²x - 1/3 |

Thanks guys!!! Even got 2 options :) The more the merrier :spin: |

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