- **Trigonometry**
(*http://mymathforum.com/trigonometry/*)

- - **Getting one expression to another**
(*http://mymathforum.com/trigonometry/330568-getting-one-expression-another.html*)

Getting one expression to anotherHello, I have the following expression: 1/((sinx)^2) - 4/3, and I want to get to the following expression: 1/((tgx)^2) - 1/3. I wasn't able to find the right identities, maybe you could help? Thanks! |

$\dfrac{1}{\sin^2{x}} - 1 - \dfrac{1}{3}$ $(\csc^2{x} - 1) - \dfrac{1}{3}$ $\cot^2{x} - \dfrac{1}{3}$ $\dfrac{1}{\tan^2{x}} - \dfrac{1}{3}$ |

1/sin²x - 4/3 = (cos²x + sin²x)/sin²x - 4/3 = cos²x/sin²x + 1 - 4/3 = 1/tan²x - 1/3 |

Thanks guys!!! Even got 2 options :) The more the merrier :spin: |

All times are GMT -8. The time now is 04:30 AM. |

Copyright © 2019 My Math Forum. All rights reserved.