My Math Forum Inverse of sine squared

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 March 11th, 2012, 05:39 AM #1 Newbie   Joined: Jan 2010 Posts: 17 Thanks: 0 Inverse of sine squared In a book that I am using, it is written that " 7 sin^2x-1=0 turns into x=sin^-1 +-(square root of)1/7. If I want to move sin^2 to the other side, is it right for the sine to be turned into the inverse of sine or sin^-1? If it is right, what is the rule of math that covers this? Thank you in advance for your hospitality.
 March 11th, 2012, 05:48 AM #2 Senior Member   Joined: Jul 2011 Posts: 227 Thanks: 0 Re: Inverse of sine squared $7\sin^2(x)-1=0$ $\Rightarrow 7\sin^2(x)=1$ $\Rightarrow \sin^2(x)=\frac{1}{7}$ $\Rightarrow \sin(x)=\pm \sqrt{\frac{1}{7}}$ $\Rightarrow x=\arcsin\left(\pm \sqrt{\frac{1}{7}}\right)$
 March 11th, 2012, 05:59 AM #3 Newbie   Joined: Jan 2010 Posts: 17 Thanks: 0 Re: Inverse of sine squared Wow, I get it now. Thank you very much.

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# sin squared inverse

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