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 February 15th, 2012, 02:12 PM #1 Member   Joined: Feb 2012 Posts: 78 Thanks: 0 Trig Help I need to know how to do the following: 1.) Ethan is watching a satellite launch from an observation spot 6 miles away. Find the angle of elevation to the satellite, which is at a height of 3.8 miles. 2.) Find the Amp, period and phase shift of y=7+sin((3pi/4)x+(1/2)) This is what I have so far: Amp = 1 period = (8/3) phase shift = shift to the left (2/3pi) Is this right? 3.) Evaluate the following expression using a calculator if necessary. If the answer does not exist, write "does not exist". $\displaystyle \csc^{-1} (5)$ Last edited by skipjack; August 26th, 2019 at 12:39 PM. February 15th, 2012, 03:05 PM #2 Global Moderator   Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,963 Thanks: 1148 Math Focus: Elementary mathematics and beyond Re: Trig Help 1) arctan(19/30) 2) Amplitude (peak to peak): 2, sin is � 1, 7 � 1, 6 to 8 etc. Period: 8/3, 2$\pi$/(3$\pi$/4) = 8/3. Phase shift: 2/(3?) units to the left. Solve 3?x/4 = -1/2. 3) 1/sin(5), which exists since $\pi$ < 5 < 2$\pi$. Last edited by skipjack; August 26th, 2019 at 12:41 PM. February 15th, 2012, 03:12 PM #3 Member   Joined: Feb 2012 Posts: 78 Thanks: 0 Re: Trig Help So the phase shift is: To the left; (1/2)? February 15th, 2012, 03:20 PM #4 Global Moderator   Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,963 Thanks: 1148 Math Focus: Elementary mathematics and beyond Re: Trig Help Phase shift: 2/(3$\pi$) units to the left. Solve 3$\pi$x/4 = -1/2. Sorry, I should have mentioned that this should be solved for x. Last edited by skipjack; August 26th, 2019 at 12:42 PM. February 15th, 2012, 03:24 PM #5 Member   Joined: Feb 2012 Posts: 78 Thanks: 0 Re: Trig Help Here is what I got for the phase shift -c/b= -1/2/(3pi)/4 = -1/2 x 4/(3pi) = -4/(6pi) = -2/(3pi) Therefore you phase shift to the left -2/(3pi) or do you take the reciprocal of that and shift to the right? February 15th, 2012, 03:25 PM   #6
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Re: Trig Help

Quote:
 Originally Posted by greg1313 Phase shift: 2/(3$\pi$) units to the left. Solve 3$\pi$x/4 = -1/2., sorry, I should have mentioned that this should be solved for x.
Yes but b is not part of x I thought?

Last edited by skipjack; August 26th, 2019 at 12:42 PM. February 15th, 2012, 03:47 PM #7 Senior Member   Joined: Jan 2012 Posts: 131 Thanks: 0 Re: Trig Help y=�A+BSinC(x�D) A=Vertical Shift +up,-down B=Amplitude on Y axis. C=Horizontal Compression/Stretch. Period=2?/C D=Horizontal shift, + to the left, - to the right. y=7+sin((3pi/4)x+(1/2)) y=7+Sin(3?/4)(x+(1/2)/(3?/4)) y=7+Sin(3?/4)(x+(2/3?)) February 15th, 2012, 09:43 PM #8 Global Moderator   Joined: Dec 2006 Posts: 20,966 Thanks: 2215 (3). $\displaystyle \csc^{\small-1}(5) = \sin^{\small-1}\left(\frac{\small1}{\small5}\right) = 0.201...$ Last edited by skipjack; August 26th, 2019 at 12:43 PM. Tags trig Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post cr1pt0 Trigonometry 2 September 5th, 2013 06:11 PM mathgeek11 Trigonometry 5 April 9th, 2013 08:53 PM Chee Trigonometry 7 December 11th, 2011 09:50 AM IneedofHelp Trigonometry 1 October 17th, 2011 02:38 AM Bihzad Algebra 1 March 11th, 2009 01:48 PM

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