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January 31st, 2012, 07:31 PM   #1
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2 inverse trig graphs

Hey everyone. Sorry to post another topic, but i thought this would be easy to find on google, to help me with , but i cant find it.

All im really lookin for is someone to let me know if my answers are right, and if not, then how i can fix them

Anyways, i was asked to graph y=sin(arsinc)
So i graphed the line y=x with the doman as -1 to 1 and the range as -pi/2 to pi/2

Then i neded to graph y=arsin(sinx)
So i graphed the line y=x with the domain as -pi/2 to pi/2 and the range as -1 to 1

This is just wat i came up with based on my profs notes, but im not sure if they are right, or even how i came up with them. I just tried a few things and thought this made sense. haha

if someone could let me know if this is right, i'd greatly appreciate it !
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January 31st, 2012, 10:43 PM   #2
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Re: 2 inverse trig graphs

ooops, typos in the functions i wrote.
i meant y=sin(arcsinx)
and arcsin(sinx)
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February 1st, 2012, 06:47 AM   #3
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Re: 2 inverse trig graphs

If you are graphing y = x on a certain domain (say, [-1, 1], then why is the range different?
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