July 12th, 2011, 10:47 PM  #1 
Newbie Joined: Jul 2011 Posts: 7 Thanks: 0  Trig Identities
Here's another one if you're up for it mark tan x 1  =  sin x  2tan x cos x  2 
July 12th, 2011, 10:48 PM  #2 
Newbie Joined: Jul 2011 Posts: 7 Thanks: 0  Re: Trig Identities
darn that didn't work out (tan x)/(sin x  2tan x) = 1/(cos x  2) 
July 12th, 2011, 10:49 PM  #3 
Newbie Joined: Jul 2011 Posts: 7 Thanks: 0  Re: Trig Identities
*prove that gah sorry for the triple post I cant edit my own posts 
July 12th, 2011, 10:58 PM  #4 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,209 Thanks: 517 Math Focus: Calculus/ODEs  Re: Trig Identities
We are given: On the left side, try multiplying by 
July 12th, 2011, 11:02 PM  #5  
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,209 Thanks: 517 Math Focus: Calculus/ODEs  Re: Trig Identities Quote:
 
July 13th, 2011, 08:06 AM  #6  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407  Re: Trig Identities Hello, Gokias! Another approach . . . Quote:  
July 13th, 2011, 08:37 AM  #7 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,900 Thanks: 1093 Math Focus: Elementary mathematics and beyond  Re: Trig Identities 
July 13th, 2011, 09:07 AM  #8  
Global Moderator Joined: Nov 2009 From: Northwest Arkansas Posts: 2,766 Thanks: 4  Re: Trig Identities Quote:
 
July 13th, 2011, 09:24 AM  #9 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,900 Thanks: 1093 Math Focus: Elementary mathematics and beyond  Re: Trig Identities 
July 13th, 2011, 01:20 PM  #10 
Senior Member Joined: Sep 2010 Posts: 101 Thanks: 0  Re: Trig Identities
Hahahaha, good one! 

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