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 October 10th, 2007, 03:47 PM #1 Member   Joined: Sep 2007 Posts: 49 Thanks: 0 secant We know that secant function is the reciprocal of cosine function. sec(angle)=1/cos(angle). I know how cosine graph looks like, but how can we base on cosine graph, to draw the secant graph. Suppose a point is (45,0.7) on the cosine graph, then is this point on the secant graph becoming the reciprocal (1/45,1/0.7)? I don't really think so. Hope you can help, thanks.
October 10th, 2007, 03:52 PM   #2
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Re: secant

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 Originally Posted by mia6 We know that secant function is the reciprocal of cosine function. sec(angle)=1/cos(angle). I know how cosine graph looks like, but how can we base on cosine graph, to draw the secant graph. Suppose a point is (45,0.7) on the cosine graph, then is this point on the secant graph becoming the reciprocal (1/45,1/0.7)? I don't really think so. Hope you can help, thanks.
You take the reciprocal of the function, not of the angle. So sec (45deg)=1/cos(45deg).

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