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 October 16th, 2009, 01:54 PM #1 Senior Member   Joined: Apr 2009 Posts: 201 Thanks: 0 trivial proof on limits? Hi, I saw this question on a past test: prove that x->3 1/(x-4) = -1 this looks very trivial, doesn't this just follow from the reciprocal limit law? take delta to be min(1/2, epsilon/2) since all we have to do here is prove that you can plug "a" into the equation thanks
 October 16th, 2009, 02:05 PM #2 Senior Member   Joined: Oct 2007 From: Chicago Posts: 1,701 Thanks: 3 Re: trivial proof on limits? Basically, yeah. We know that that function is continuous at 3 (prove it), so -1=f(3)= lim x->3 f(x)
 December 2nd, 2009, 07:42 PM #3 Senior Member   Joined: Dec 2009 Posts: 150 Thanks: 0 Re: trivial proof on limits? quotient of continuous functions are continuous wherever the denominator is nonzero. The limit of a quotient is the quotient of the limits if the limit of the denominator is nonzero. The top is constant so the limit is the same, the bottom is linear and you can take lim(x-4) = lim(x) - lim(4) = lim(x) -4 = 3 -4 = -1. Done.

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